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BJP leader Mukul Roy will appear before CBI

Kolkata: BJP leader Mukul Roy will appear before the Central Bureau of Investigation (CBI) at 3 pm on Saturday in response to a second notice in the Narada sting case.

Mr. Roy, who was the number two leader in the Trinamool Congress, is named along with 13 other accused in the Narada sting case.

The sting operation was carried out by Narda chief executive Matthew Samuel in which the politician was assured to get the work done for money.

Earlier, the CBI had given him notice to appear at Nizam Palace at 11 am on Friday.

After which Mr. Roy sought more time to appear before the investigating officers of the CBI. CBI arrested senior IPS officer SMH Mirza on Thursday.

This is the first arrest since Sting surfaced in 2016.

It is noteworthy that Mr. Roy was summoned to examine the voice sample on Friday.

His representative, who could not attend the scheduled time,

went to the CBI office at Nizam Palace and handed over a letter requesting that he be given some more time as he is busy with party work.

BJP leader Mukul Rai was accused earlier

Mukul Rai was once considered the leader of Trinamool Congress number two.

This sting operation is also during the same period.

An IPS officer has already been arrested in order to investigate Sting.

However, BJP leader Mukul Rai has emerged as a strong leader for the party in the last Lok Sabha elections as well.

On the other hand, his name has been repeatedly mentioned in the investigation of Saradha scam.

The statement of some people arrested in this case is also against them.

The CBI has not been able to trace former Kolkata Police Commissioner Rajiv Kumar in the Saradha scam.

Who have been continuously filing bail applications from one court to another.

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